Bonjour mais comment est ce possible 5/3-1/4=17/12 et 5/6+1/3=7/6 7/6-1/4=11/12

Bonjour,

A=5/3-1/4

A=5*4/(3*4)-1*3/(4*3)

A=20/12-3/12

A=17/12

B=5/6+1/3

B=5/6+1*2/(3*2)

B=5/6+2/6

B=7/6

C=7/6-1/4

C=7*2/(6*2)-3*1/(3*4)

C=14/12-3/12

C=11/12

Bonjour ;

[tex]\dfrac{5}{3}-\dfrac{1}{4}=\dfrac{5\times4}{3\times4}-\dfrac{1\times3}{3\times4}=\dfrac{20}{12}-\dfrac{3}{12}=\dfrac{20-3}{12}=\dfrac{17}{12}\ .[/tex]

[tex]\dfrac{5}{6}+\dfrac{1}{3}=\dfrac{5}{6}+\dfrac{1\times2}{3\times2}=\dfrac{5}{6}+\dfrac{2}{6}=\dfrac{5+2}{6}=\dfrac{7}{6}\ .[/tex]

[tex]\dfrac{7}{6}-\dfrac{1}{4}=\dfrac{7\times2}{6\times2}-\dfrac{1\times3}{4\times3}=\dfrac{14}{12}-\dfrac{3}{12}=\dfrac{14-3}{12}=\dfrac{11}{12}\ .[/tex]