Mathématiques

Question

vous pouver m aider svp a factoriser 6x+2=4x+9
6x+2=4x+9
3x-11-6x-10=7+8x-12-7
4(2x-1)-7(4x+2)=-6(x-1)+4
(2x-3)(2x+1)=4x^2-x+7
-9x+7=5x-2
6(2x-1)-3(7x-5)=0
-(4-9x)+2x=5(3+2x)
(2x-3)(2x+3)=(2x-5)^2

1 Réponse

  • 6x+2=4x+9

    6x-4x = 9-2

    2x = 7

    x = 7/2

    3x-11-6x-10=7+8x-12-7

    -3x - 21 = 8x - 12

    -3x - 8x = -12 + 21

    -11x = 9

    x = -9/11

    4(2x-1)-7(4x+2)=-6(x-1)+4

    8x - 4 - 28x - 14 = -6x + 6 + 4

    tu continues - voir au-dessu

    (2x-3)(2x+1)=4x²-x+7

    4x² + 2x - 6x - 3 = 4x² - x +  7

    -4x - 3 = -x + 7

    et tu continues

    -9x+7=5x-2

    tu as compris

    6(2x-1)-3(7x-5)=0

    12x - 6 - 21x + 15 = 0

    -9x = - 9

    x = 1

    -(4-9x)+2x=5(3+2x)

    -4 + 9x + 2x = 15 + 2x

    et tu continues

    (2x-3)(2x+3)=(2x-5)^2

    4x² + 6x - 6x + 9 = 4x² - 20x + 25

    9 = - 20x + 25

    tu finis

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